#include <iostream>
using namespace std;
void TopDownMergeSort(int A[], int B[], int n);
void TopDownSplitMerge(int B[], int iBegin, int iEnd, int A[]);
void TopDownMerge(int A[], int iBegin, int iMiddle, int iEnd, int B[]);
void CopyArray(int A[], int iBegin, int iEnd, int B[]);
int main()
{
cin.tie(NULL);
int N;
cin >> N;
int* X = new int[N];
for (int i = 0; i < N; i++)
cin >> X[i];
int* Y = new int[N];
TopDownMergeSort(X, Y, N);
for (int i = 0; i < N; i++)
cout << X[i] << "\n";
}
// Array A[] has the items to sort; array B[] is a work array.
void TopDownMergeSort(int A[], int B[], int n)
{
CopyArray(A, 0, n, B); // duplicate array A[] into B[]
TopDownSplitMerge(B, 0, n, A); // sort data from B[] into A[]
}
// Sort the given run of array A[] using array B[] as a source.
// iBegin is inclusive; iEnd is exclusive (A[iEnd] is not in the set).
void TopDownSplitMerge(int B[], int iBegin, int iEnd, int A[])
{
if (iEnd - iBegin < 2) // if run size == 1
return; // consider it sorted
// split the run longer than 1 item into halves
int iMiddle = (iEnd + iBegin) / 2; // iMiddle = mid point
// recursively sort both runs from array A[] into B[]
TopDownSplitMerge(A, iBegin, iMiddle, B); // sort the left run
TopDownSplitMerge(A, iMiddle, iEnd, B); // sort the right run
// merge the resulting runs from array B[] into A[]
TopDownMerge(A, iBegin, iMiddle, iEnd, B);
}
// Left source half is A[ iBegin:iMiddle-1].
// Right source half is A[iMiddle:iEnd-1 ].
// Result is B[ iBegin:iEnd-1 ].
void TopDownMerge(int A[], int iBegin, int iMiddle, int iEnd, int B[])
{
int i = iBegin, j = iMiddle;
// While there are elements in the left or right runs...
for (int k = iBegin; k < iEnd; k++) {
// If left run head exists and is <= existing right run head.
if (i < iMiddle && (j >= iEnd || A[i] <= A[j])) {
B[k] = A[i];
i = i + 1;
}
else {
B[k] = A[j];
j = j + 1;
}
}
}
void CopyArray(int A[], int iBegin, int iEnd, int B[])
{
for (int k = iBegin; k < iEnd; k++)
B[k] = A[k];
}
MergeSort는 https://ko.wikipedia.org/wiki/%ED%95%A9%EB%B3%91_%EC%A0%95%EB%A0%AC 에서 참조했다.
댓글
댓글 쓰기